Hi all,
I've read http://www.web-polygraph.org/docs/userman/auth.html many times,
but I cannot see how to map the user:pass combinations below:
yxxxx1:yyyyy1
yxxxx2:yyyyy2
...
yxxxx999:yyyyy999
credentials = "yxxxx[1-998]:yyyyy[1-998]";
Will give me yxxxx1:yyyyy1, yxxxx1:yyyyy2, yxxxx1:yyyyy3
Pointers please.
Regards,
Virgil
-- WebCentral Pty Ltd Australia's #1 Internet Web Hosting Company Level 5, 100 Wickham St. Infrastructure Design and Engineering PO Box 930, Fortitude Valley. email: virgil_at_webcentral.com.au Queensland, Australia 4006. phone: +61 7 3230 7332Received on Tue Nov 25 2003 - 18:11:23 MST
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